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7+13p-2p^2=0
a = -2; b = 13; c = +7;
Δ = b2-4ac
Δ = 132-4·(-2)·7
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-15}{2*-2}=\frac{-28}{-4} =+7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+15}{2*-2}=\frac{2}{-4} =-1/2 $
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